LESSON ASSIGNMENT

 

LESSON 2 Fractions.

LESSON ASSIGNMENT Frames 2-1 through 2-37.

MATERIALS REQUIRED Pencil, eraser.

LESSON OBJECTIVES After completing this lesson, you should be able to:

2-1. Write a fraction to describe the part of a whole.

2-2. Add, subtract, multiply, and divide fractions.

2-3. Convert a number to an improper fraction.

2-4. Reduce a fraction.

SUGGESTION Work the following exercises (numbered frames) in numerical order. Write the answer in the space provided in the frame. After you have completed a frame, check your answer against solution given in the shaded area of the following frame. The final frame contains review exercises for Lesson 2. These exercises will help you to achieve the lesson objectives.

___________________________________________________________________

FRAME 2-1.

DEFINITION. A fraction is a part of a whole. If you cut a pie into 12 equal pieces and ate 5 pieces, you would have eaten 5/12 (five-twelfths) of the pie (5/12 means "5 parts out of 12 equal parts").

1

Consider the pie mentioned above. What fraction of the pie still remains? (Use the "pie" chart above.)

Remaining pie:

 

___________________________________________________________________

FRAME 2-2.

In text, fractions are usually written in a horizontal form, such as "5/12," for ease of reading. When performing calculations, fractions are usually written in a vertical form, such as 5.

12

The top (or first) number is called the numerator. The number on bottom (or second number) is called the denominator.

In the fraction 5/12, "5" is the and

"12" is the .

Solution to Frame 2-1.

7

12

___________________________________________________________________

FRAME 2-3.

MULTIPLYING AND DIVIDING FRACTIONS. It may seem strange to begin with multiplication and division of fractions rather than addition and subtraction. The multiplication and division functions are relatively simple operations, however, and multiplication must be understood before addition and subtraction of some fractions can be performed.

To multiply fractions:

(1) Multiply the numerators together;

(2) Multiply the denominators together; and

(3) Place the product of the numerators over the product of the denominators.

For example: 2 X 4 = 2 x 4 = 8

3 5 3 x 5 15

You work 1 X 2 = 1 x 2 = ?

this one. 3 7 3 x 7 ?

Solution to Frame 2-2.

5 numerator

12 denominator

___________________________________________________________________

FRAME 2-4.

Let's try four more.

a. 1 X 1 = b. 3 X 1 = ___

2 2 4 2

 

c. 2 X 1 X 7 = d. 3 X 2 = ___

7 8 10 2 6

Solution to Frame 2-3.

2

21

___________________________________________________________________

FRAME 2-5.

When you divide a fraction by another fraction, invert (flip) the second fraction and multiply the fractions.

 

For example: 2 ) 4 = 2 X 5 = 2x5 = 10

3 5 3 4 3x4 12

 

To solve the problem 1/2 ) 1/4 (one-half divided by one-fourth), you would invert the (choose one -- 1/2; 1/4) and multiply.

NOTE: Just like 18 ) 6 asks, "How many groups of 6 are in 18?", so

1/2 ) 1/4 asks, "How many one-fourths are in one-half?" (or, "How many quarters are in a half?").

Solution to Frame 2-4.

a.

b. 3

4 8

c. 14 d. 6

560 12

___________________________________________________________________

FRAME 2-6.

Solve these problems.

 

a. 1/4 ) 1/2 =

 

b. 1/2 ) 1/6 =

 

c. 2/3 ) 3/7 =

 

d. 3/7 ) 2/3 =

Solution to Frame 2-5.

1

4

1/2 ) 1/4 =

1/2 x 4/1 = 4/2 = 2

(There are two quarters in a half)

___________________________________________________________________

FRAME 2-7.

ADDING AND SUBTRACTING FRACTIONS. Have you ever heard someone say, "You can't add apples and oranges"? Well, there is a similar rule when working with fractions -- you can't add fractions with different denominators.

This means that, in order for two fractions to be added together, the

numbers must be the same.

a. Top

b. Bottom

Solution to Frame 2-6.

a.

b. 6

4 2

c. 14 d. 9

9 14

___________________________________________________________________

FRAME 2-8.

If two fractions have the same denominator (called a "common denominator"), you add the fractions by simply adding the numerators together and putting the sum over the common denominator. YOU DO NOT ADD THE DENOMINATORS TOGETHER. For example:

3 + 1 = 3 + 1 = 4

8 8 8 8

 

More than two fractions can be added together at one time as long as they all have the same denominator. Complete the following exercise.

2 + 1 + 5 + 4 =

17 17 17 17

Solution to Frame 2-7.

b. Bottom

___________________________________________________________________

FRAME 2-9.

When you add two fractions with the same denominator together, you add the numerators and put the sum over the common denominator. Likewise, when you subtract two fractions with the same denominator, you subtract the numerators and put the difference over the common denominator.

For example: 4 _ 1 = 4-1 = 3

8 8 8 8

Solve the following subtraction problems:

a. 9 _ 5 =

12 12

b. 17 _ 5 =

31 31

c. 5 _ 2 =

10 10

Solution to Frame 2-8.

2+1+5+4 = 12

17 17

___________________________________________________________________

FRAME 2-10.

Adding fractions with common denominators is like adding apples and

apples. For example, saying 3 + 1 = 4

8 8 8

is much like saying "3 apples plus 1 apple equals 4 apples," with "apples" being "eighths."

But what if you have 3 + 1 ? What is "3 apples plus 1 orange"?

8 4

This problem cannot be solved as long as the fractions are in their present form because they do not have the same .

Solution to Frame 2-9.

a. 9 - 5 = 4

12 12

b. 17 - 5 = 12

31 31

c. 5 - 2 = 3

10 10

___________________________________________________________________

FRAME 2-11.

Have you ever had a friend named James? Some people may call him "James," some may call him "Jim," some may call him "Jimmy," and his little sister may even call him "Bo," but he is the same person regardless of what you call him. Fractions also have many different "names" or forms, and you can change the fraction's name when you need to.

If you can't work with the denominator of a fraction, change the "name" of the fraction until it has the that you do want.

Solution to Frame 2-10.

denominator

___________________________________________________________________

FRAME 2-12.

The four "pies" shown below are the same size, but have been sliced differently. The same amount of pie has been removed (the shaded area), but the number of slices removed are different. The amount of the shaded area is the same in all four cases, but the name of the fraction is different in each case. Name the shaded areas.

1 = 2 = ? = ?

? ? 12 ?

Solution to Frame 2-11.

denominator

___________________________________________________________________

FRAME 2-13.

So, if you're "adding apples and oranges," see if you can change the "apple" name of the fraction to the "orange" name (or vice versa).

Consider this problem again: 3 + 1

8 4

Can you change the name of the second fraction (the fraction with the smaller denominator) so that it will have the same denominator as the other fraction? (Refer back to Frame 2-12.)

1 = ?

4 8

Solution to Frame 2-12.

1 = 2 = 3 = 4

4 8 12 16

___________________________________________________________________

FRAME 2-14.

If two fractions have different denominators, see if the larger denominator is a multiple of the smaller. That is, can the smaller denominator be multiplied by a whole number and the product be the larger denominator? If so, then the larger denominator can be the common denominator.

8 is a multiple of 4 because 4 x = 8.

Solution to Frame 2-13.

1 = 2

4 8

___________________________________________________________________

FRAME 2-15.

Therefore, : 3 + 1 = 3 + 2 = 3 + 2 = ?

8 4 8 8 8 8

[Adding 2/8 is the same as adding 1/4 since both are forms of the same number (value).]

Solution to Frame 2-14.

4 x 2 = 8

__________________________________________________________________

FRAME 2-16.

You know that if you multiply a number by "1," then the product is the original number. For example, 4 x 1 = 4. The same is true if the number is a fraction. For example: 1 X 1 = 1

2 2

 

The number "1" has several forms, or names.

Some are 1 , 2 , 3, and 4.

1 2 3 4

In each case, the numerator and the denominator are the same. Multiplying a fraction by one of the forms of "1" allows you to change the appearance of the fraction so that it has a different denominator. Now let's find some different names (forms) of the fraction 1/2.

(Remember, multiplying a fraction by "1" [regardless of the form of "1" you use] yields a fraction whose actual value has not changed, even if its form has changed.)

1 X 2 = 2 ; 1 X 3 = 3 ; 1 X 10 = 10 ; 1 X 3473 = ?

2 2 4 2 3 6 2 10 20 2 3473

Solution to Frame 2-15.

5

8

___________________________________________________________________

FRAME 2-17.

Let's look at the problem 1 + 1

2 6

The denominators are not the same, so you must find a common denominator. Since "6" is a multiple of "2" (2 x 3 = 6), you can change 1/2 to a form that has the same denominator as the other fraction.

1 X. 3 = ?

2 3 ?

Solution to Frame 2-16.

3473

6946

___________________________________________________________________

FRAME 2-18.

Since 3/6 is the same as 1/2, you can substitute (switch) 3/6 for 1/2 and work the problem.

1 + 1 = 3 + 1 = 3 + 1 = ?

2 6 6 6 6 6

Solution to Frame 2-17.

3

6

___________________________________________________________________

FRAME 2-19.

Subtraction of fractions works very similar to addition. Find the common denominator, change one or both of the fractions until they have the same denominator, and subtract the numerators.

Work these problems on your own:

1 _ 1 =

2 6

1 _ 1 =

2 10

Solution to Frame 2-18.

4

6

___________________________________________________________________

FRAME 2-20.

What happens, though, when one denominator is not a multiple of the other. If you can't change the apples to oranges or oranges to apples, maybe you can change them both to grapefruit. That is, find a common denominator to which both denominators can be changed.

The common denominator will be a multiple of the _________________

of the first fraction and a multiple of the of the second fraction.

Solution to Frame 2-19.

3-1 = 2

6 6

5-1 = 4

10 10

___________________________________________________________________

FRAME 2-21.

Suppose you had two fractions, one with a denominator of "3" and the other with a denominator of "4." One method of getting a common denominator is to multiply the denominators together. For a problem with two denominators ("3" and "4"), a common denominator would be "12" (3 x 4 = 12 and 4 x 3 = 12).

Finish solving the following problem:

1 + 1 = 1 X 4 + 1 X 3 = 4 + ? = ?

3 4 3 4 4 3 12 12

Solution to Frame 2-20.

denominator

denominator

___________________________________________________________________

FRAME 2-22.

Solve this subtraction problem:

5 _ 3 =

6 8

Solution to Frame 2-21.

= 4 + 3 = 4+3 = 7

12 12 12 12

___________________________________________________________________

FRAME 2-23.

Although multiplying the denominators together will always give you a common denominator, sometimes a smaller common denominator can be found. Consider the previous problem? Can you think of a common denominator for 5/6 and 3/8 that is smaller than 48? What number will both 6 and 8 divide into and the quotients be whole numbers (no remainders)?

____________

Work the problem 5/6 – 3/8 again using the smaller common denominator. (Divide the denominator into the common denominator and multiply the numerator by the quotient.)

Solution to Frame 2-22.

= 5x8 _ 3x6 = 40-18=

6x8 8x6 48

22

48

___________________________________________________________________

FRAME 2-24.

You can add and subtract fractions in the same problem. Just make sure that each denominator divides evenly into the common denominator. Try this problem.

1 _ 1 + 1 _ 1 + 1 _ 1

2 3 5 7 9 11

Solution to Frame 2-23.

24

= 5x4 _ 3x3 = 20-9= 11

6x4 8x3 24 24

___________________________________________________________________

FRAME 2-25.

The solution to Frame 2-24 is shown below (not sufficient space in column to right). The problem is worked two ways. The first shows the problem worked with the common denominator being the product of all of the denominators (2x3x5x7x9 = 1890). The second shows the problem being worked with a lower common denominator (2x5x7x9 = 630). Did you notice that the denominator "3" divides evenly into the denominator "9"?

1 _ 1 + 1 _ 1 + 1 =

2 3 5 7 9

1x3x5x7x9 _ 1x2x5x7x9 + 1x2x3x7x9 _ 1x2x3x5x9 + 1x2x3x5x7=

2x3x5x7x9 3x2x5x7x9 5x2x3x7x9 7x2x3x5x9 9x2x3x5x7

945 _ 630 + 378 _ 270 + 210 = (945-630)+(378-270)+210 =

1890 1890 1890 1890 1890 1890

315+108+210 = 633

1890 1890

 

NOTE: There are several ways of adding and subtracting the numerators. One way is shown above. Another (and usually better) way is to add all of the pluses (positives) together, add all of the minuses (negatives) together, and subtract as shown below.

(945+378+210) – (630+270) = 1533 – 900 = 633

 

Using 630 (2x5x7x9) as the common denominator

 

1x5x7x9 _ 1x2x5x7x3 + 1x2x7x9 _ 1x2x5x9 + 1x2x5x7 =

2x5x7x9 3x2x5x7x3 5x2x7x9 7x2x5x9 9x2x5x7

315 _ 210 + 126 _ 90 + 70 = (315-210)+(126-90)+70 =

630 630 630 630 630 630

105+36+70 = 211

630 630

 

The converted fractions can also be added and subtracted as below:

(315+126+70) – (210+90) = 511 – 300 = 211

630 630 630

Solution to Frame 2-24.

633 or 211

1890 630

___________________________________________________________________

FRAME 2-26.

REDUCING FRACTIONS. Usually, you will want your answers "reduced." That is, you will want to use the name (form) of the fraction that has the smallest denominator possible that will still allow both the numerator and denominator to remain whole numbers. The fraction is then "reduced to its lowest form."

Below are three fractions, each in different forms. Circle the reduced form of each fraction.

 

3 = 1 = 4 = 1/2 ; 2 = 1 = 54 ; 2.5 = 10 = 5

6 2 8 1 3 1.5 81 4 16 8

Solution to Frame 2-25.

No problem was given in Frame 2-25

___________________________________________________________________

FRAME 2-27.

To reduce a fraction, find the largest whole number that can be divided into both the numerator and denominator evenly (no remainders). Then divide both the numerator and denominator by that number.

When reducing a fraction you must divide both the and the

by the same number.

Solution to Frame 2-26.

1 2 5

2 3 8

Remember, both the numerator and the denominator must be whole numbers (not fractions or decimals).

___________________________________________________________________

FRAME 2-28.

For example, the fraction 8/12 can be reduced as shown below.

8 = 8 ) 4 = 2

12 12 ) 4 3

Sometimes you may have to divide more than once to reach the reduced form. For instance, the example can also be worked as follows:

8 = 8 ) 2 = 4

12 12 ) 2 6

But this number can be reduced further: 4 = 4 ) 2 = 2

6 6 ) 2 3

Reduce the following fractions.

5 = 27 =

10 30

 

107 = 3 =

107 17

Solution to Frame 2-27.

numerator; denominator

OR

denominator; numerator

___________________________________________________________________

FRAME 2-29.

Solve the following problems. Reduce the answers.

1 + 3 =

10 10

2 _ 1 =

3 6

3 X 2 =

8 3

7 ) 1 =

8 4

Solution to Frame 2-28.

5 ) 5 = 1

10 ) 5 2

27 ) 3 = 9

30 ) 3 10

107 ) 107 = 1 = 1

107 ) 107 1

3 ) 1 = 3

17 ) 1 17

___________________________________________________________________

FRAME 2-30.

Instead of looking for the biggest number that divides into both the numerator and denominator evenly (called the "largest common denominator"), you can divide by prime numbers. A prime number is a number that cannot be divided by any whole number other than itself and 1 without leaving a remainder. Prime numbers include 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, and so on. Begin with "2." If "2" divides into both the numerator and denominator evenly (no remainder), then reduce the fraction by two. Take the new fraction and try to reduce the new numerator and denominator by "2" again. Continue until the fraction can no longer be reduced by 2. Then do the same with the next prime number ("3"). Continue until there is no whole number (other than 1) that will divide into both the numerator and the denominator evenly. For example:

48 = 48 ) 2 = 24 ; 24 ) 2 = 12 ; 12 ) 2 = 6 ; 6 ) 3 = 2

72 72 ) 2 36 36 ) 2 18 18 ) 2 9 9 ) 3 3

NOTE: On 6/9, 2 will divide evenly into 6 but not into 9. Therefore, you go to the next prime number.

A variation is to break both the numerator and the denominator down into prime factors (prime numbers that yield the original number when multiplied). If the same factor appears in both the numerator and denominator, mark it out. Mark out factors one at a time. [For example, if you have "2" as a factor 3 times in the numerator but only twice in the denominator, you can only mark out two of the "2's" in the numerator.] When you are finished, multiple the remaining factors to obtain the reduced fraction. For example:

48 = 2 x 2 x 2 x 2 x 3 = 2 x 2 x 2 x 2 x 3 = 2

72 2 x 2 x 2 x 3 x 3 2 x 2 x 2 x 3 x 3 3

 

Reduce 200/375 by this method.

Solution to Frame 2-29.

4 = 2

10 5

3 = 1

6 2

6 = 1

24 4

7x4 = 28 = 7

8x1 8 2

___________________________________________________________________

FRAME 2-31.

IMPROPER FRACTIONS. Notice that the answer to the last problem in Frame 2-29 is unusual in that the fraction has a numerator that is larger than the denominator. Such a fraction is called an improper fraction.

An improper fraction is a fraction in which the numerator is equal to or larger than the denominator.

A proper fraction is a fraction in which the numerator is less than the denominator.

A combination of a whole number and a fraction, such as three and one-half (3 1/2), is called a mixed number.

3/5 is a(n) .

5/3 is a(n) .

1 2/3 is a(n) .

Solution to Frame 2-30.

200 = 2x2x2x5x5 =

375 3x5x5x5

2x2x2x5x5 = 2x2x2=

3x5x5x5 3x5

8

15

___________________________________________________________________

FRAME 2-32.

When you worked the problem 7/8 divided by 1/4, you came up with an improper fraction (7/2) as the answer. When your answer is an improper fraction, you will usually change it to its mixed number form (this is also referred to as "reducing"). To change an improper fraction to a mixed number, divide the numerator by the denominator and put the remainder (if any) over the denominator.

Reduce 7/2 to a mixed number.

Solution to Frame 2-31.

3

5 proper fraction

5

3 improper fraction

1 2/3 mixed number

___________________________________________________________________

FRAME 2-33.

Reduce the following improper fractions. If the remainder is zero, then the improper fraction reduces to a whole number.

 

10 =

3

100 =

14

20 =

4

Solution to Frame 2-32.

3

7/2 = 2/ 7 = 3 1/2

6

1

___________________________________________________________________

FRAME 2-34.

In working some problems, it may be more convenient to multiply by a fraction rather than a mixed number. In such cases, you need to know how to change a mixed number into an improper fraction.

One way of thinking about a mixed number is as a whole number plus a fraction. To change a mixed number to an improper fraction

(1) Change the whole number to an improper fraction with the same

denominator as the fraction, then

(2) Add the two fractions together.

Example: 5 2/3 = 5 + 2 = 5 x 3 + 2 = 15 + 2 = 15 + 2 = 17

1 3 1 x 3 3 3 3 3 3

 

Change the following mixed numbers to improper fractions.

2 1/2 =

 

3 2/5 =

 

14 7/23 =

Solution to Frame 2-33.

10/3 = 3 1/3

100/14 = 7 2/14

= 7 1/7

20/4 = 5

___________________________________________________________________

FRAME 2-35.

A shortcut for changing a mixed number to an improper fraction is to:

(1) Multiply the whole number by the denominator,

(2) Add the numerator to the product, and

(3) Put the sum over the denominator.

For example: 5 2/3 = 5 x 3 + 2 = 15 + 2 = 17

3 3 3

Change the following mixed numbers to improper fractions using the shortcut method:

2 1/3

1 1/10

4 2/5

Solution to Frame 2-34.

2 1/2 = 5/2

3 2/5 = 17/5

14 7/23 = 329/23

___________________________________________________________________

FRAME 2-36.

To change a whole number to an improper fraction:

(1) Choose the desired denominator,

(2) Multiply the whole number by the denominator, and

(3) Place the product over the denominator.

 

For example:

3 = how may fifths? 3 = 3 x 5 = 15

5 5

 

Fill in the following:

2 = __

2

 

7 = __

5

 

10 = __

3

Solution to Frame 2-35.

2 1/3 = 7/3

1 1/10 = 11/10

4 2/5 = 22/5

___________________________________________________________________

FRAME 2-37.

Remember " (a + b) (c + d) = ac + ad + bc + bd" from Frame 1-35? This general formula can be applied to multiplying mixed numbers. For example, in the problem 2 1/2 x 3 1/3, let a = 2, b = 1/2, c = 3, and d = 1/3.

 

Solve the problem using the algebraic formula, then solve it using improper fractions. Your answers should be the same.

Solution to Frame 2-36.

2 = 4/2

7 = 35/5

10 = 30/3

___________________________________________________________________

FRAME 2-38

SELF-TEST. Complete the self-test exercises below. After you have worked all the exercises, turn to the solution sheet on the following page and check your work. For each exercise answered incorrectly, reread the appropriate lesson frame(s) and rework the exercise.

1. Add and reduce:

a. 1 + 2 =

3 3

b. 1 + 1 =

2 8

c. 3 + 1 =

4 3

2. Subtract and reduce:

a. 12 _ 10 =

7 7

b. 7 _ 1 =

8 2

c. 3 _ 1 =

8 3

3. Multiply and reduce:

a. 7 X 2 =

2 5

b. 2 X 1 =

3 4

4. Divide and reduce:

a. 2 ) 3 =

5 8

b. 1 ) 1 =

5 10

5. Change to improper fractions:

a. 6 2/5 =

 

b. 7 = __

4

Solution to Frame 2-37.

8 1/3

(a + b) (c + d) =

ac + ad + bc + bd

(2 + 1/2) (3 + 1/3) =

(2)(3) + (2)(1/3) +

(1/2)(3) + (1/2)(1/3) =

6 + 2/3 + 3/2 + 1/6 =

6 + 4/6 + 9/6 + 1/6 =

6 + 14/6 =

6 + 2 2/6 =

(6+2) + 1/3 =

8 1/3

 

CHECK:

2 1/2 x 3 1/3 =

5/2 x 10/3 =

50/6 = 8 2/6 = 8 1/3